Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
Bu | 2451 | 131 | 4 | 32.7500 |
En | 105 | 11 | 1 | 11.0000 |
Son | 114 | 10 | 1 | 10.0000 |
öğrenci | 171 | 9 | 1 | 9.0000 |
Daha | 187 | 9 | 1 | 9.0000 |
araya | 87 | 9 | 1 | 9.0000 |
açısından | 132 | 9 | 1 | 9.0000 |
Her | 247 | 17 | 2 | 8.5000 |
O | 115 | 8 | 1 | 8.0000 |
temsil | 75 | 7 | 1 | 7.0000 |
neden | 175 | 13 | 2 | 6.5000 |
15 | 127 | 12 | 2 | 6.0000 |
tebrik | 35 | 6 | 1 | 6.0000 |
internet | 88 | 6 | 1 | 6.0000 |
izin | 87 | 6 | 1 | 6.0000 |
yeterli | 99 | 6 | 1 | 6.0000 |
oy | 73 | 6 | 1 | 6.0000 |
tespit | 113 | 11 | 2 | 5.5000 |
görev | 241 | 16 | 3 | 5.3333 |
anlamına | 30 | 5 | 1 | 5.0000 |
Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
Prof | 482 | 2 | 30 | 0.0667 |
gerekmektedir | 202 | 1 | 13 | 0.0769 |
adet | 150 | 1 | 12 | 0.0833 |
Dr | 112 | 1 | 10 | 0.1000 |
edilmektedir | 71 | 1 | 10 | 0.1000 |
etti | 262 | 2 | 18 | 0.1111 |
verildi | 76 | 1 | 8 | 0.1250 |
bulundu | 67 | 1 | 8 | 0.1250 |
güzel | 155 | 1 | 8 | 0.1250 |
yýlýnda | 131 | 2 | 15 | 0.1333 |
defa | 79 | 1 | 7 | 0.1429 |
etmektedir | 123 | 1 | 7 | 0.1429 |
edilmiştir | 74 | 1 | 7 | 0.1429 |
beri | 81 | 1 | 7 | 0.1429 |
önemlidir | 70 | 1 | 7 | 0.1429 |
eder | 210 | 3 | 20 | 0.1500 |
bulunduğu | 70 | 1 | 6 | 0.1667 |
çerçevesinde | 127 | 1 | 6 | 0.1667 |
sahiptir | 97 | 1 | 6 | 0.1667 |
aldı | 80 | 1 | 6 | 0.1667 |
In this subsection, we compute the ratio of the number of right neighbors and the number of left neighbors. Again, we look for words with extreme ratios:
Data for first table:
select word,w.freq,aa.cnt, bb.cnt,aa.cnt/bb.cnt as r from words w, (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where w_id=aa.w1_id and aa.w1_id=bb.w2_id order by r desc limit 20;
Diagram data:
select aa.cnt, bb.cnt from (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where aa.w1_id=bb.w2_id;
5.1.7.1 Number of NN co-occurrences vs. Frequency I
5.1.7.2 Number of NN co-occurrences vs. Frequency II